Best of five
- A. 4
- B. 10
- C. 25
- D. 16.7
- E. 40
A trial reports postoperative haemorrhage in 10% of controls and 6% with an intervention. What is the number needed to treat to prevent one haemorrhage?
Absolute risk reduction is 0.10 minus 0.06 = 0.04; NNT is 1/0.04 = 25.
A. 4: This confuses the four-percentage-point absolute reduction with NNT.
B. 10: This is the control event percentage, not the reciprocal absolute reduction.
C. 25: Absolute risk reduction is 0.10 minus 0.06 = 0.04; NNT is 1/0.04 = 25.
D. 16.7: This is approximately the reciprocal of the treated event rate.
E. 40: This incorrectly treats the absolute reduction as 2.5%.
If the treated event rate were 8%, the absolute reduction would be 2% and the NNT would be 50.
Independent Clinora preparation material; not official JCIE content, an accredited programme or a substitute for local policy and specialist judgement.
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